(32x-5y^20)^2/5

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Solution for (32x-5y^20)^2/5 equation: 


x in (-oo:+oo)

((32*x-(5*y^20))^2)/5 = 0

((32*x-5*y^20)^2)/5 = 0

32*x-5*y^20 = 0 // + -5*y^20

32*x = -(-5*y^20) // : 32

x = (-(-5*y^20))/32

x = (5*y^20)/32

x in { (5*y^20)/32, (5*y^20)/32 }

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